What is (x+1)^2-3(x+2) ?

The solution to (x+1)^2-3(x+2) is x^2-x-5

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simplify (x+1)^2-3(x+2)

simplify

(x + 1)^{2} - 3 (x + 2)

x^{2} - x - 5

Solution steps

(x + 1)^{2} - 3 (x + 2)

Expand

(x + 1)^{2} : x^{2} + 2 x + 1

= x^{2} + 2 x + 1 - 3 (x + 2)

Expand

- 3 (x + 2) : - 3 x - 6

= x^{2} + 2 x + 1 - 3 x - 6

Group like terms

= x^{2} + 2 x - 3 x + 1 - 6

Add similar elements:

2 x - 3 x = - x

= x^{2} - x + 1 - 6

Subtract the numbers:

1 - 6 = - 5

= x^{2} - x - 5

\frac{x - 2}{x + 2}

b^{2} - (b - 2 x)^{2}

\frac{3}{- 2 + 13}

\frac{x ^{2} + 5 x + 6}{x ^{2} - 9}

- \frac{1}{6} - \frac{8}{9}