What is (7+3i)-(6-4i) ?

The solution to (7+3i)-(6-4i) is 1+7i

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simplify (7+3i)-(6-4i)

simplify

(7 + 3 i) - (6 - 4 i)

1 + 7 i

Solution steps

(7 + 3 i) - (6 - 4 i)

Group the real part and the imaginary part of the complex number

(a + bi) - (c + d i) = (a - c) + (b - d) i

= (7 - 6) + (3 - (- 4)) i

Simplify

(7 - 6) + (3 - (- 4)) i : 1 + 7 i

= 1 + 7 i

1^{2} + i^{2}

15 (2 \frac{1}{3})

\frac{56}{49}

- 10 - (- 4)

\frac{11}{14} \div \frac{5}{6}