What is 6i-(14-i)+(5-3i) ?

The solution to 6i-(14-i)+(5-3i) is -9+4i

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simplify 6i-(14-i)+(5-3i)

simplify

6 i - (14 - i) + (5 - 3 i)

- 9 + 4 i

Solution steps

6 i - (14 - i) + (5 - 3 i)

Apply rule:

a + (b + c) = a + b + c

- (14 - i) + (5 - 3 i) = - (14 - i) + 5 - 3 i

= 6 i - (14 - i) + 5 - 3 i

Group like terms

= 6 i - 3 i - (14 - i) + 5

Add similar elements:

6 i - 3 i = 3 i

= 3 i - (14 - i) + 5

Remove parentheses:

- (a + bi) = - a - bi

= 3 i + - 14 - (- 1) i + 5

Group like terms

= 3 i - (- 1) i - 14 + 5

Add similar elements:

3 i - (- 1) i = 4 i

= 4 i - 14 + 5

Add the numbers:

- 14 + 5 = - 9

= 4 i - 9

Rewrite in standard complex form:

- 9 + 4 i

= - 9 + 4 i

∣ 1 - 3 ∣

5 k + 3 k^{3} + 7 k + 9 k^{3}

\frac{( 2 + i ) ( 3 + 2 i )}{( 1 - i ) i ^{3}}

\frac{5}{8} - \frac{1}{7}

(- 4 x^{3})^{\frac{2}{3}}