What are the solutions to the equation 5x^2-21x+11=7 ?

The solutions to the equation 5x^2-21x+11=7 are x=4,x= 1/5

Find the zeros of 5x^2-21x+11=7

The zeros of 5x^2-21x+11=7 are x=4,x= 1/5

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5 x^{2} - 21 x + 11 = 7

x = 4, x = \frac{1}{5}

Solution steps

5 x^{2} - 21 x + 11 = 7

Move

7

to the left side

5 x^{2} - 21 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 21 ) \pm ( - 21 ) ^{2} - 4 \cdot 5 \cdot 4}{2 \cdot 5}

(- 21)^{2} - 4 \cdot 5 \cdot 4 = 19

x_{1, 2} = \frac{- ( - 21 ) \pm 19}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 21 ) + 19}{2 \cdot 5}, x_{2} = \frac{- ( - 21 ) - 19}{2 \cdot 5}

x = \frac{- ( - 21 ) + 19}{2 \cdot 5} : 4

x = \frac{- ( - 21 ) - 19}{2 \cdot 5} : \frac{1}{5}

The solutions to the quadratic equation are:

x = 4, x = \frac{1}{5}

lo g_{5} (4)

2 x + 7 < 5

4 x^{2} + 16

3 - y = 11

5 r = \frac{5}{2}

What are the solutions to the equation 5x^2-21x+11=7 ?
The solutions to the equation 5x^2-21x+11=7 are x=4,x= 1/5
Find the zeros of 5x^2-21x+11=7
The zeros of 5x^2-21x+11=7 are x=4,x= 1/5