What is factor x^8+4x^4y^4+16y^8 ?

The solution to factor x^8+4x^4y^4+16y^8 is (x^4+4y^4+2x^2y^2)(x^4+4y^4-2x^2y^2)

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factor x^8+4x^4y^4+16y^8

factor

x^{8} + 4 x^{4} y^{4} + 16 y^{8}

(x^{4} + 4 y^{4} + 2 x^{2} y^{2}) (x^{4} + 4 y^{4} - 2 x^{2} y^{2})

Solution steps

x^{8} + 4 x^{4} y^{4} + 16 y^{8}

Add and subtract

4 x^{4} y^{4}

= x^{8} + 8 x^{4} y^{4} + 16 y^{8} - 4 x^{4} y^{4}

Factor

x^{8} + 8 x^{4} y^{4} + 16 y^{8} : (x^{4} + 4 y^{4})^{2}

= (x^{4} + 4 y^{4})^{2} - 4 x^{4} y^{4}

Apply exponent rules

= (x^{4} + 4 y^{4})^{2} - (2 x^{2} y^{2})^{2}

Factor

(x^{4} + 4 y^{4})^{2} - (2 x^{2} y^{2})^{2} : (x^{4} + 4 y^{4} + 2 x^{2} y^{2}) (x^{4} + 4 y^{4} - 2 x^{2} y^{2})

= (x^{4} + 4 y^{4} + 2 x^{2} y^{2}) (x^{4} + 4 y^{4} - 2 x^{2} y^{2})

\frac{( 3 s ^{- 3} ) ^{5}}{3 s ^{- 2}}

64 - m^{6}

\frac{7}{13} \times \frac{2}{3}

(1 + 0.0001)^{\frac{1}{0.0001}}

(2 x^{2} + 5 y^{4})^{3}

What is factor x^8+4x^4y^4+16y^8 ?
The solution to factor x^8+4x^4y^4+16y^8 is (x^4+4y^4+2x^2y^2)(x^4+4y^4-2x^2y^2)