What are the solutions to the equation x^2+2x-23=0 ?

The solutions to the equation x^2+2x-23=0 are x=-1+2sqrt(6),x=-1-2sqrt(6)

Find the zeros of x^2+2x-23=0

The zeros of x^2+2x-23=0 are x=-1+2sqrt(6),x=-1-2sqrt(6)

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x^{2} + 2 x - 23 = 0

x = - 1 + 26, x = - 1 - 26

Solution steps

x^{2} + 2 x - 23 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 23 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 23) = 46

x_{1, 2} = \frac{- 2 \pm 4 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 4 6}{2 \cdot 1}, x_{2} = \frac{- 2 - 4 6}{2 \cdot 1}

x = \frac{- 2 + 4 6}{2 \cdot 1} : - 1 + 26

x = \frac{- 2 - 4 6}{2 \cdot 1} : - 1 - 26

The solutions to the quadratic equation are:

x = - 1 + 26, x = - 1 - 26

∣ x + 7 ∣ + 5 \leq 7

- 3 - 8 \leq - 23

4 - a^{2} - 2 ab - b^{2}

(9^{\frac{3}{8}})^{4}

3 x^{2} - 6 x - 5 x + 10

What are the solutions to the equation x^2+2x-23=0 ?
The solutions to the equation x^2+2x-23=0 are x=-1+2sqrt(6),x=-1-2sqrt(6)
Find the zeros of x^2+2x-23=0
The zeros of x^2+2x-23=0 are x=-1+2sqrt(6),x=-1-2sqrt(6)