What is ((x-5)^2)/(x^2-1)>= 0 ?

The solution to ((x-5)^2)/(x^2-1)>= 0 is x 1

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((x-5)^2)/(x^2-1)>= 0

\frac{( x - 5 ) ^{2}}{x ^{2} - 1} \geq 0

x < - 1 or x > 1

Solution steps

\frac{( x - 5 ) ^{2}}{x ^{2} - 1} \geq 0

Factor

\frac{( x - 5 ) ^{2}}{x ^{2} - 1} : \frac{( x - 5 ) ^{2}}{( x + 1 ) ( x - 1 )}

\frac{( x - 5 ) ^{2}}{( x + 1 ) ( x - 1 )} \geq 0

Identify the intervals

x < - 1 or x > 1

\frac{1}{n}

t, 1 - (1 + t)^{2} - r = \frac{( p \cdot t )}{m}

2 x - 2 > 2 x - 4

What is ((x-5)^2)/(x^2-1)>= 0 ?
The solution to ((x-5)^2)/(x^2-1)>= 0 is x<-1\lor x>1