What is (x^2-9)/(x^2-4x+3) ?

The solution to (x^2-9)/(x^2-4x+3) is (x+3)/(x-1)

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simplify (x^2-9)/(x^2-4x+3)

simplify

\frac{x ^{2} - 9}{x ^{2} - 4 x + 3}

\frac{x + 3}{x - 1}

Solution steps

\frac{x ^{2} - 9}{x ^{2} - 4 x + 3}

Factor

x^{2} - 9 : (x + 3) (x - 3)

= \frac{( x + 3 ) ( x - 3 )}{x ^{2} - 4 x + 3}

Factor

x^{2} - 4 x + 3 : (x - 1) (x - 3)

= \frac{( x + 3 ) ( x - 3 )}{( x - 1 ) ( x - 3 )}

Cancel the common factor:

x - 3

= \frac{x + 3}{x - 1}

2 lo g_{4} (9)

\frac{5 x}{x}

5 x^{3} - 20 x y^{2}

\frac{y ^{2} - x ^{2}}{x - y}