What are the solutions to the equation 25x^2+4=0 ?

The solutions to the equation 25x^2+4=0 are x= 2/5 i,x=-2/5 i

Find the zeros of 25x^2+4=0

The zeros of 25x^2+4=0 are x= 2/5 i,x=-2/5 i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

25 x^{2} + 4 = 0

x = \frac{2}{5} i, x = - \frac{2}{5} i

Solution steps

25 x^{2} + 4 = 0

Move

4

to the right side

25 x^{2} = - 4

Divide both sides by

25

x^{2} = - \frac{4}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{4}{25}, x = - - \frac{4}{25}

- \frac{4}{25} = \frac{2}{5} i

- - \frac{4}{25} = - \frac{2}{5} i

x = \frac{2}{5} i, x = - \frac{2}{5} i

∣ x + 8 ∣ \geq - 8

(i - 2)^{3} - (i - 2)

∣ 6 - 3 x ∣ \geq 12

3 x + 2 = 5 x

81 x^{2} - 36

What are the solutions to the equation 25x^2+4=0 ?
The solutions to the equation 25x^2+4=0 are x= 2/5 i,x=-2/5 i
Find the zeros of 25x^2+4=0
The zeros of 25x^2+4=0 are x= 2/5 i,x=-2/5 i