What is (2c^2-18)/(c^2+c-6) ?

The solution to (2c^2-18)/(c^2+c-6) is (2(c-3))/(c-2)

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simplify (2c^2-18)/(c^2+c-6)

simplify

\frac{2 c ^{2} - 18}{c ^{2} + c - 6}

\frac{2 ( c - 3 )}{c - 2}

Solution steps

\frac{2 c ^{2} - 18}{c ^{2} + c - 6}

Factor

2 c^{2} - 18 : 2 (c + 3) (c - 3)

= \frac{2 ( c + 3 ) ( c - 3 )}{c ^{2} + c - 6}

Factor

c^{2} + c - 6 : (c - 2) (c + 3)

= \frac{2 ( c + 3 ) ( c - 3 )}{( c - 2 ) ( c + 3 )}

Cancel the common factor:

c + 3

= \frac{2 ( c - 3 )}{c - 2}

1 6^{- 3}

(n^{2} + 2 n + 1) (n^{2} - 2 n - 1)

3 x^{2} - x y - 4 y^{2}

- \frac{1}{3} \cdot (- 6)

\frac{5}{8} \div \frac{3}{10}

What is (2c^2-18)/(c^2+c-6) ?
The solution to (2c^2-18)/(c^2+c-6) is (2(c-3))/(c-2)