What is (3u-1)(u+2)+7u(u+1) ?

The solution to (3u-1)(u+2)+7u(u+1) is 10u^2+12u-2

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simplify (3u-1)(u+2)+7u(u+1)

simplify

(3 u - 1) (u + 2) + 7 u (u + 1)

10 u^{2} + 12 u - 2

Solution steps

(3 u - 1) (u + 2) + 7 u (u + 1)

Expand

(3 u - 1) (u + 2) : 3 u^{2} + 5 u - 2

= 3 u^{2} + 5 u - 2 + 7 u (u + 1)

Expand

7 u (u + 1) : 7 u^{2} + 7 u

= 3 u^{2} + 5 u - 2 + 7 u^{2} + 7 u

Group like terms

= 3 u^{2} + 7 u^{2} + 5 u + 7 u - 2

Add similar elements:

3 u^{2} + 7 u^{2} = 10 u^{2}

= 10 u^{2} + 5 u + 7 u - 2

Add similar elements:

5 u + 7 u = 12 u

= 10 u^{2} + 12 u - 2

\frac{( \frac{25}{a} - a )}{5 + a}

108 x^{6} + 27 x^{6}

2 a^{4} b - 4 a b^{4} - 6 a^{4} b^{4}

x^{2} (y + 3) - (y + 3)

(a^{2} + b^{3})^{2}

What is (3u-1)(u+2)+7u(u+1) ?
The solution to (3u-1)(u+2)+7u(u+1) is 10u^2+12u-2