What is the domain of f(a)=(a^2-9)/(a^2-3a) ?

The domain of f(a)=(a^2-9)/(a^2-3a) is a 3

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domain of f(a)=(a^2-9)/(a^2-3a)

domain

f (a) = \frac{a ^{2} - 9}{a ^{2} - 3 a}

a < 0 or 0 < a < 3 or a > 3

Interval Notation

(- \infty, 0) \cup (0, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

a = 3, a = 0

The function domain

a < 0 or 0 < a < 3 or a > 3

10 (10 x + 7 y - 6)

8 x^{2} - 80 x

- 3 \frac{5}{6} - 4 \frac{3}{8}

\frac{8}{5} - 2

5 x^{4} - 80

What is the domain of f(a)=(a^2-9)/(a^2-3a) ?
The domain of f(a)=(a^2-9)/(a^2-3a) is a<0\lor 0<a<3\lor a>3