What are the solutions to the equation 6z^2+11z=-4 ?

The solutions to the equation 6z^2+11z=-4 are z=-1/2 ,z=-4/3

Find the zeros of 6z^2+11z=-4

The zeros of 6z^2+11z=-4 are z=-1/2 ,z=-4/3

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6 z^{2} + 11 z = - 4

z = - \frac{1}{2}, z = - \frac{4}{3}

Decimal Notation

z = - 0.5, z = - 1.33333 \dots

Solution steps

6 z^{2} + 11 z = - 4

Move

4

to the left side

6 z^{2} + 11 z + 4 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 6 \cdot 4}{2 \cdot 6}

1 1^{2} - 4 \cdot 6 \cdot 4 = 5

z_{1, 2} = \frac{- 11 \pm 5}{2 \cdot 6}

Separate the solutions

z_{1} = \frac{- 11 + 5}{2 \cdot 6}, z_{2} = \frac{- 11 - 5}{2 \cdot 6}

z = \frac{- 11 + 5}{2 \cdot 6} : - \frac{1}{2}

z = \frac{- 11 - 5}{2 \cdot 6} : - \frac{4}{3}

The solutions to the quadratic equation are:

z = - \frac{1}{2}, z = - \frac{4}{3}

2 x^{2} = 14

8 (y - 1) > 24

2 x^{2} + 5 x + 4 = 0

- 9 g + 9 > - g - 7

2 t + (t - 4)^{2} = 5 t (t - 4) + 24

What are the solutions to the equation 6z^2+11z=-4 ?
The solutions to the equation 6z^2+11z=-4 are z=-1/2 ,z=-4/3
Find the zeros of 6z^2+11z=-4
The zeros of 6z^2+11z=-4 are z=-1/2 ,z=-4/3