What is (10x^2-4x+3)-(7x^2-3x+13) ?

The solution to (10x^2-4x+3)-(7x^2-3x+13) is 3x^2-x-10

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simplify (10x^2-4x+3)-(7x^2-3x+13)

simplify

(10 x^{2} - 4 x + 3) - (7 x^{2} - 3 x + 13)

3 x^{2} - x - 10

Solution steps

(10 x^{2} - 4 x + 3) - (7 x^{2} - 3 x + 13)

Apply rule:

(a) = a

(10 x^{2} - 4 x + 3) = 10 x^{2} - 4 x + 3

= 10 x^{2} - 4 x + 3 - (7 x^{2} - 3 x + 13)

Apply the distributive law:

- (a - b) = - a + b

- (7 x^{2} - 3 x + 13) = - 7 x^{2} + 3 x - 13

= 10 x^{2} - 4 x + 3 - 7 x^{2} + 3 x - 13

Group like terms

= 10 x^{2} - 7 x^{2} - 4 x + 3 x + 3 - 13

Add similar elements:

10 x^{2} - 7 x^{2} = 3 x^{2}

= 3 x^{2} - 4 x + 3 x + 3 - 13

Add similar elements:

- 4 x + 3 x = - x

= 3 x^{2} - x + 3 - 13

Subtract the numbers:

3 - 13 = - 10

= 3 x^{2} - x - 10

(x + y)^{2} - z^{2}

\frac{3 15}{9}

\frac{1}{1 + 4 i} + \frac{1}{1 + 7 i}

\frac{3 x ^{5}}{x ^{3}}

∣ 3 - π ∣

What is (10x^2-4x+3)-(7x^2-3x+13) ?
The solution to (10x^2-4x+3)-(7x^2-3x+13) is 3x^2-x-10