What are the solutions to the equation x^2-4x=52 ?

The solutions to the equation x^2-4x=52 are x=2(1+sqrt(14)),x=2(1-sqrt(14))

Find the zeros of x^2-4x=52

The zeros of x^2-4x=52 are x=2(1+sqrt(14)),x=2(1-sqrt(14))

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x^{2} - 4 x = 52

x = 2 (1 + 14), x = 2 (1 - 14)

Solution steps

x^{2} - 4 x = 52

Move

52

to the left side

x^{2} - 4 x - 52 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 52 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 52) = 414

x_{1, 2} = \frac{- ( - 4 ) \pm 4 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 14}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 4 14}{2 \cdot 1}

x = \frac{- ( - 4 ) + 4 14}{2 \cdot 1} : 2 (1 + 14)

x = \frac{- ( - 4 ) - 4 14}{2 \cdot 1} : 2 (1 - 14)

The solutions to the quadratic equation are:

x = 2 (1 + 14), x = 2 (1 - 14)

- 4 u < - 16

\frac{( x - 1 )}{( x + 2 ) ( x + 5 )} \leq 0

(5 - 3 x) - (- 4 x + 6) = (8 x + 1) - 3 (2 x + 3)

7 x < 21 or x - 4 > 1

What are the solutions to the equation x^2-4x=52 ?
The solutions to the equation x^2-4x=52 are x=2(1+sqrt(14)),x=2(1-sqrt(14))
Find the zeros of x^2-4x=52
The zeros of x^2-4x=52 are x=2(1+sqrt(14)),x=2(1-sqrt(14))