What is expand (3x^2-x+2)^2 ?

The solution to expand (3x^2-x+2)^2 is 9x^4-6x^3+13x^2-4x+4

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expand (3x^2-x+2)^2

expand

(3 x^{2} - x + 2)^{2}

9 x^{4} - 6 x^{3} + 13 x^{2} - 4 x + 4

Solution steps

(3 x^{2} - x + 2)^{2}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(3 x^{2} - x + 2)^{2} = (3 x^{2} - x + 2) (3 x^{2} - x + 2)

= (3 x^{2} - x + 2) (3 x^{2} - x + 2)

Distribute parentheses

= 3 x^{2} \cdot 3 x^{2} + 3 x^{2} (- x) + 3 x^{2} \cdot 2 - x \cdot 3 x^{2} - x (- x) - x \cdot 2 + 2 \cdot 3 x^{2} + 2 (- x) + 2 \cdot 2

Simplify

3 x^{2} \cdot 3 x^{2} + 3 x^{2} (- x) + 3 x^{2} \cdot 2 - x \cdot 3 x^{2} - x (- x) - x \cdot 2 + 2 \cdot 3 x^{2} + 2 (- x) + 2 \cdot 2 : 9 x^{4} - 6 x^{3} + 13 x^{2} - 4 x + 4

= 9 x^{4} - 6 x^{3} + 13 x^{2} - 4 x + 4

(1 - 5 i) + (2 + 10 i)

(12 y) (- 5 x) (- \frac{5}{6} x^{4} y)

\frac{x}{x - 3} - \frac{2}{3 x + 4}

(2 a^{2} b c^{4})^{3}

x^{3} + 2 x^{2} + 8 x + 16

What is expand (3x^2-x+2)^2 ?
The solution to expand (3x^2-x+2)^2 is 9x^4-6x^3+13x^2-4x+4