What is expand (2x-5)(5x^2+4x+7) ?

The solution to expand (2x-5)(5x^2+4x+7) is 10x^3-17x^2-6x-35

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expand (2x-5)(5x^2+4x+7)

expand

(2 x - 5) (5 x^{2} + 4 x + 7)

10 x^{3} - 17 x^{2} - 6 x - 35

Solution steps

(2 x - 5) (5 x^{2} + 4 x + 7)

Distribute parentheses

= 2 x \cdot 5 x^{2} + 2 x \cdot 4 x + 2 x \cdot 7 - 5 \cdot 5 x^{2} - 5 \cdot 4 x - 5 \cdot 7

Simplify

2 x \cdot 5 x^{2} + 2 x \cdot 4 x + 2 x \cdot 7 - 5 \cdot 5 x^{2} - 5 \cdot 4 x - 5 \cdot 7 : 10 x^{3} - 17 x^{2} - 6 x - 35

= 10 x^{3} - 17 x^{2} - 6 x - 35

\frac{- 16}{8}

\frac{3.9 - 4}{3. 9 ^{2} - 5 ( 3.9 ) + 4}

3 y + 3 y + 5 + 7 x^{3} - y - 6 - 7 x^{3}

\frac{e ^{0}}{( 1 + e ^{0} ) ^{2}}

(\frac{- 2}{3})^{4}

What is expand (2x-5)(5x^2+4x+7) ?
The solution to expand (2x-5)(5x^2+4x+7) is 10x^3-17x^2-6x-35