What is factor y^3-3y^2-4y+12 ?

The solution to factor y^3-3y^2-4y+12 is (y-3)(y+2)(y-2)

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factor y^3-3y^2-4y+12

factor

y^{3} - 3 y^{2} - 4 y + 12

(y - 3) (y + 2) (y - 2)

Solution steps

y^{3} - 3 y^{2} - 4 y + 12

= (y^{3} - 3 y^{2}) + (- 4 y + 12)

Factor out

y^{2}

from

y^{3} - 3 y^{2} : y^{2} (y - 3)

Factor out

- 4

from

- 4 y + 12 : - 4 (y - 3)

= y^{2} (y - 3) - 4 (y - 3)

Factor out common term

y - 3

= (y - 3) (y^{2} - 4)

Factor

y^{2} - 4 : (y + 2) (y - 2)

= (y - 3) (y + 2) (y - 2)

\frac{4 t ^{3}}{( 3 t ^{3} ) ^{5}}

\frac{7 x ^{3} y ^{2}}{14 x ^{5} y}

\frac{4}{7} \div \frac{6}{11}

(\frac{1}{4 - x ^{2}})^{2}

(122)^{10}

What is factor y^3-3y^2-4y+12 ?
The solution to factor y^3-3y^2-4y+12 is (y-3)(y+2)(y-2)