What is 5(n^2+n)-3(n^2-2n) ?

The solution to 5(n^2+n)-3(n^2-2n) is 2n^2+11n

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simplify 5(n^2+n)-3(n^2-2n)

simplify

5 (n^{2} + n) - 3 (n^{2} - 2 n)

2 n^{2} + 11 n

Solution steps

5 (n^{2} + n) - 3 (n^{2} - 2 n)

Expand

5 (n^{2} + n) : 5 n^{2} + 5 n

= 5 n^{2} + 5 n - 3 (n^{2} - 2 n)

Expand

- 3 (n^{2} - 2 n) : - 3 n^{2} + 6 n

= 5 n^{2} + 5 n - 3 n^{2} + 6 n

Group like terms

= 5 n^{2} - 3 n^{2} + 5 n + 6 n

Add similar elements:

5 n^{2} - 3 n^{2} = 2 n^{2}

= 2 n^{2} + 5 n + 6 n

Add similar elements:

5 n + 6 n = 11 n

= 2 n^{2} + 11 n

(- 4 x^{2})^{- 1}

\frac{20}{10}

\frac{- 24}{3}

e^{l n (\frac{1}{x})}

(5 - \frac{3}{2})^{2} - 2