What is 3y^2-3+2x-2x+4y^2-6+5 ?

The solution to 3y^2-3+2x-2x+4y^2-6+5 is 7y^2-4

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simplify 3y^2-3+2x-2x+4y^2-6+5

simplify

3 y^{2} - 3 + 2 x - 2 x + 4 y^{2} - 6 + 5

7 y^{2} - 4

Solution steps

3 y^{2} - 3 + 2 x - 2 x + 4 y^{2} - 6 + 5

Add similar elements:

2 x - 2 x = 0

= 3 y^{2} - 3 + 4 y^{2} - 6 + 5

Group like terms

= 3 y^{2} + 4 y^{2} - 3 - 6 + 5

Add similar elements:

3 y^{2} + 4 y^{2} = 7 y^{2}

= 7 y^{2} - 3 - 6 + 5

Add the numbers:

- 3 - 6 + 5 = - 4

= 7 y^{2} - 4

21 u^{3} v^{7} + 7 u^{2} v^{5}

- \frac{1}{3} + \frac{4}{3}

- 5 (x + h)^{2}

(3 x^{2} - x + 1) + (15 - 9 x - 2 x^{2})

\frac{3}{5} \div \frac{4}{3}