What is (3y^7)/((2y^{-2))^{-5}} ?

The solution to (3y^7)/((2y^{-2))^{-5}} is (96)/(y^3)

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simplify (3y^7)/((2y^{-2))^{-5}}

simplify

\frac{3 y ^{7}}{( 2 y ^{- 2} ) ^{- 5}}

\frac{96}{y ^{3}}

Solution steps

\frac{3 y ^{7}}{( 2 y ^{- 2} ) ^{- 5}}

Simplify

(2 y^{- 2})^{- 5} : \frac{y ^{10}}{32}

= \frac{3 y ^{7}}{\frac{y ^{10}}{32}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{3 y ^{7} \cdot 32}{y ^{10}}

Cancel

\frac{3 y ^{7} \cdot 32}{y ^{10}} : \frac{96}{y ^{3}}

= \frac{96}{y ^{3}}

\frac{13}{13}

\frac{x ^{- 1} - 1}{x - 1}

(4 y^{4})^{2}

(\frac{1}{3 ^{- 2}})^{- 3}

9 - (- 3)^{2}

What is (3y^7)/((2y^{-2))^{-5}} ?
The solution to (3y^7)/((2y^{-2))^{-5}} is (96)/(y^3)