What is sqrt(20x^2y^{-4)} ?

The solution to sqrt(20x^2y^{-4)} is (2sqrt(5)x)/(y^2)

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simplify sqrt(20x^2y^{-4)}

simplify

20 x^{2} y^{- 4}

\frac{2 5 x}{y ^{2}}

Solution steps

20 x^{2} y^{- 4}

20 x^{2} y^{- 4} = 20 x^{2} y^{- 4}

= 20 x^{2} y^{- 4}

Apply radical rule:

a^{2} = a,

assuming

a \geq 0

x^{2} = x

= 20 x y^{- 4}

20 = 25

= 25 x y^{- 4}

Simplify

y^{- 4} : \frac{1}{y ^{2}}

= 25 x \frac{1}{y ^{2}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 5 x \cdot 1}{y ^{2}}

Multiply the numbers:

2 \cdot 1 = 2

= \frac{2 5 x}{y ^{2}}

\frac{4}{3 - 3}

(x^{2})^{n + 1}

\frac{3}{x - 1} + \frac{x}{x + 2}

\frac{- 3}{3}

What is sqrt(20x^2y^{-4)} ?
The solution to sqrt(20x^2y^{-4)} is (2sqrt(5)x)/(y^2)