What are the solutions to the equation 3x^2+9=39 ?

The solutions to the equation 3x^2+9=39 are x=sqrt(10),x=-sqrt(10)

Find the zeros of 3x^2+9=39

The zeros of 3x^2+9=39 are x=sqrt(10),x=-sqrt(10)

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3 x^{2} + 9 = 39

x = 10, x = - 10

Decimal Notation

x = 3.16227 \dots, x = - 3.16227 \dots

Solution steps

3 x^{2} + 9 = 39

Move

9

to the right side

3 x^{2} = 30

Divide both sides by

3

x^{2} = 10

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 10, x = - 10

5 x + 4 = 4 x + 2

2 x - 7 = 9

\frac{x}{4} - 3 = 5

- \frac{10}{16}

27 x^{3} + 8

What are the solutions to the equation 3x^2+9=39 ?
The solutions to the equation 3x^2+9=39 are x=sqrt(10),x=-sqrt(10)
Find the zeros of 3x^2+9=39
The zeros of 3x^2+9=39 are x=sqrt(10),x=-sqrt(10)