What is (8x-10)-(x^2-2x) ?

The solution to (8x-10)-(x^2-2x) is -x^2+10x-10

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simplify (8x-10)-(x^2-2x)

simplify

(8 x - 10) - (x^{2} - 2 x)

- x^{2} + 10 x - 10

Solution steps

(8 x - 10) - (x^{2} - 2 x)

Apply rule:

(a) = a

(8 x - 10) = 8 x - 10

= 8 x - 10 - (x^{2} - 2 x)

Apply the distributive law:

- (a - b) = - a + b

- (x^{2} - 2 x) = - x^{2} + 2 x

= 8 x - 10 - x^{2} + 2 x

Group like terms

= - x^{2} + 8 x + 2 x - 10

Add similar elements:

8 x + 2 x = 10 x

= - x^{2} + 10 x - 10

(- 6 c^{- 3} d^{9}) (2 c^{4} d^{- 5})

8 + \frac{3}{5}

m^{4} - 6 m^{3} + 9 m^{2}

\frac{2.00 1 ^{2} - 4}{2.001 - 2}