What are the solutions to the equation 4r^2+4r+1=0 ?

The solutions to the equation 4r^2+4r+1=0 are r=-1/2

Find the zeros of 4r^2+4r+1=0

The zeros of 4r^2+4r+1=0 are r=-1/2

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4 r^{2} + 4 r + 1 = 0

r = - \frac{1}{2}

Decimal Notation

r = - 0.5

Solution steps

4 r^{2} + 4 r + 1 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

4^{2} - 4 \cdot 4 \cdot 1 = 0

r_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 4}

r = \frac{- 4}{2 \cdot 4}

\frac{- 4}{2 \cdot 4} = - \frac{1}{2}

r = - \frac{1}{2}

The solution to the quadratic equation is:

r = - \frac{1}{2}

6 x^{2} - 54 x

(8 x^{4})^{2}

∣ 3 x + 1 ∣ - 1 < 2

- 3 t - 5 < 6 t + 17

x - 9.9 = 2.1

What are the solutions to the equation 4r^2+4r+1=0 ?
The solutions to the equation 4r^2+4r+1=0 are r=-1/2
Find the zeros of 4r^2+4r+1=0
The zeros of 4r^2+4r+1=0 are r=-1/2