What is (3xy^{-3})^{-2} ?

The solution to (3xy^{-3})^{-2} is (y^6)/(9x^2)

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simplify (3xy^{-3})^{-2}

simplify

(3 x y^{- 3})^{- 2}

\frac{y ^{6}}{9 x ^{2}}

Solution steps

(3 x y^{- 3})^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(3 x y^{- 3})^{- 2} = \frac{1}{( 3 x y ^{- 3} ) ^{2}}

= \frac{1}{( 3 x y ^{- 3} ) ^{2}}

Simplify

(3 x y^{- 3})^{2} : \frac{9 x ^{2}}{y ^{6}}

= \frac{1}{\frac{9 x ^{2}}{y ^{6}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{y ^{6}}{9 x ^{2}}

42 j^{2} k - 78 j k^{3} + 66 j^{3} k^{4}

9 (7 r - 3 s + 10)

7 + 57

- 6 a + 12 b - 17 a - 30 b + 4 a + 2 b

32 x^{8} - 50