What are the solutions to the equation x^2+11x-10=0 ?

The solutions to the equation x^2+11x-10=0 are x=(-11+sqrt(161))/2 ,x=(-11-sqrt(161))/2

Find the zeros of x^2+11x-10=0

The zeros of x^2+11x-10=0 are x=(-11+sqrt(161))/2 ,x=(-11-sqrt(161))/2

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x^{2} + 11 x - 10 = 0

x = \frac{- 11 + 161}{2}, x = \frac{- 11 - 161}{2}

Decimal Notation

x = 0.84428 \dots, x = - 11.84428 \dots

Solution steps

x^{2} + 11 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot (- 10) = 161

x_{1, 2} = \frac{- 11 \pm 161}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 11 + 161}{2 \cdot 1}, x_{2} = \frac{- 11 - 161}{2 \cdot 1}

x = \frac{- 11 + 161}{2 \cdot 1} : \frac{- 11 + 161}{2}

x = \frac{- 11 - 161}{2 \cdot 1} : \frac{- 11 - 161}{2}

The solutions to the quadratic equation are:

x = \frac{- 11 + 161}{2}, x = \frac{- 11 - 161}{2}

- (1 + \frac{2}{3}) + \frac{1}{6} (- 2)

x^{2} + 3 x - 18

3 - (- 1)

6 x - 60 y

\frac{( n + 1 ) ^{2}}{( n + 2 ) ^{2}}

What are the solutions to the equation x^2+11x-10=0 ?
The solutions to the equation x^2+11x-10=0 are x=(-11+sqrt(161))/2 ,x=(-11-sqrt(161))/2
Find the zeros of x^2+11x-10=0
The zeros of x^2+11x-10=0 are x=(-11+sqrt(161))/2 ,x=(-11-sqrt(161))/2