What are the solutions to the equation (x-5)^2=24 ?

The solutions to the equation (x-5)^2=24 are x=2sqrt(6)+5,x=-2sqrt(6)+5

Find the zeros of (x-5)^2=24

The zeros of (x-5)^2=24 are x=2sqrt(6)+5,x=-2sqrt(6)+5

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(x - 5)^{2} = 24

x = 26 + 5, x = - 26 + 5

Decimal Notation

x = 9.89897 \dots, x = 0.10102 \dots

Solution steps

(x - 5)^{2} = 24

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 5 = 24 : x = 26 + 5

Solve

x - 5 = - 24 : x = - 26 + 5

The solutions to the quadratic equation are:

x = 26 + 5, x = - 26 + 5

- 12 \leq 2 x - 4 < - 4

5147

6 x - 5 > - 11

\frac{5 i}{1 + 4 i}

\frac{16 !}{9 ! 7 !}

What are the solutions to the equation (x-5)^2=24 ?
The solutions to the equation (x-5)^2=24 are x=2sqrt(6)+5,x=-2sqrt(6)+5
Find the zeros of (x-5)^2=24
The zeros of (x-5)^2=24 are x=2sqrt(6)+5,x=-2sqrt(6)+5