What is (x+4)^3-2(x+4) ?

The solution to (x+4)^3-2(x+4) is x^3+12x^2+46x+56

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simplify (x+4)^3-2(x+4)

simplify

(x + 4)^{3} - 2 (x + 4)

x^{3} + 12 x^{2} + 46 x + 56

Solution steps

(x + 4)^{3} - 2 (x + 4)

Expand

(x + 4)^{3} : x^{3} + 12 x^{2} + 48 x + 64

= x^{3} + 12 x^{2} + 48 x + 64 - 2 (x + 4)

Expand

- 2 (x + 4) : - 2 x - 8

= x^{3} + 12 x^{2} + 48 x + 64 - 2 x - 8

Group like terms

= x^{3} + 12 x^{2} + 48 x - 2 x + 64 - 8

Add similar elements:

48 x - 2 x = 46 x

= x^{3} + 12 x^{2} + 46 x + 64 - 8

Subtract the numbers:

64 - 8 = 56

= x^{3} + 12 x^{2} + 46 x + 56

x^{3} \cdot x^{8}

\frac{5}{4} \cdot \frac{3}{7}

\frac{5}{x - 5} - \frac{5}{x + 5}

2 (8 v + 2)