What are the solutions to the equation 1/4 m^2+m+1=0 ?

The solutions to the equation 1/4 m^2+m+1=0 are m=-2

Find the zeros of 1/4 m^2+m+1=0

The zeros of 1/4 m^2+m+1=0 are m=-2

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\frac{1}{4} m^{2} + m + 1 = 0

m = - 2

Solution steps

\frac{1}{4} m^{2} + m + 1 = 0

Multiply both sides by

4

m^{2} + 4 m + 4 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 4 = 0

m_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 1}

m = \frac{- 4}{2 \cdot 1}

\frac{- 4}{2 \cdot 1} = - 2

m = - 2

The solution to the quadratic equation is:

m = - 2

lo g_{2} (lo g_{2} (16))

7 x + 20 = 90

\frac{3 x + 2}{2} = 13

\frac{\frac{- 27}{5}}{( - 2 )}

∣ 3 x - 7 ∣ + 1 < - 2

What are the solutions to the equation 1/4 m^2+m+1=0 ?
The solutions to the equation 1/4 m^2+m+1=0 are m=-2
Find the zeros of 1/4 m^2+m+1=0
The zeros of 1/4 m^2+m+1=0 are m=-2