What is (m^3-64)/(m^2-7m+12) ?

The solution to (m^3-64)/(m^2-7m+12) is (m^2+4m+16)/(m-3)

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simplify (m^3-64)/(m^2-7m+12)

simplify

\frac{m ^{3} - 64}{m ^{2} - 7 m + 12}

\frac{m ^{2} + 4 m + 16}{m - 3}

Solution steps

\frac{m ^{3} - 64}{m ^{2} - 7 m + 12}

Factor

m^{3} - 64 : (m - 4) (m^{2} + 4 m + 16)

= \frac{( m - 4 ) ( m ^{2} + 4 m + 16 )}{m ^{2} - 7 m + 12}

Factor

m^{2} - 7 m + 12 : (m - 3) (m - 4)

= \frac{( m - 4 ) ( m ^{2} + 4 m + 16 )}{( m - 3 ) ( m - 4 )}

Cancel the common factor:

m - 4

= \frac{m ^{2} + 4 m + 16}{m - 3}

\frac{1}{5} \cdot \frac{2}{5}

(- 1) - 10

(2 + 4 i) (3 + 5 i)

2 - (- 12)

x^{- 1} (x^{- 2} + x^{- 3})

What is (m^3-64)/(m^2-7m+12) ?
The solution to (m^3-64)/(m^2-7m+12) is (m^2+4m+16)/(m-3)