What is (3x^{-3})^{-2}x^{-2} ?

The solution to (3x^{-3})^{-2}x^{-2} is (x^4)/9

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simplify (3x^{-3})^{-2}x^{-2}

simplify

(3 x^{- 3})^{- 2} x^{- 2}

\frac{x ^{4}}{9}

Solution steps

(3 x^{- 3})^{- 2} x^{- 2}

Simplify

(3 x^{- 3})^{- 2} : \frac{x ^{6}}{9}

= \frac{x ^{6}}{9} x^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

x^{- 2} = \frac{1}{x ^{2}}

= \frac{x ^{6}}{9} \cdot \frac{1}{x ^{2}}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{x ^{6} \cdot 1}{9 x ^{2}}

Apply rule:

a \cdot 1 = a

x^{6} \cdot 1 = x^{6}

= \frac{x ^{6}}{9 x ^{2}}

Simplify

\frac{x ^{6}}{x ^{2}} : x^{4}

= \frac{x ^{4}}{9}

5 (3 x - 11) - 9 x + 30

2 \cdot \frac{3}{7}

(1)^{2} + (2)^{2}

a^{0} \cdot a^{6}

50 \cdot 20