What is (4-2i)+i(-3+5i) ?

The solution to (4-2i)+i(-3+5i) is -1-5i

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simplify (4-2i)+i(-3+5i)

simplify

(4 - 2 i) + i (- 3 + 5 i)

- 1 - 5 i

Solution steps

(4 - 2 i) + i (- 3 + 5 i)

Apply rule:

(a) = a

(4 - 2 i) = 4 - 2 i

= 4 - 2 i + i (- 3 + 5 i)

Expand

i (- 3 + 5 i) : - 3 i - 5

= 4 - 2 i - 3 i - 5

Group like terms

= - 2 i - 3 i + 4 - 5

Add similar elements:

- 2 i - 3 i = - 5 i

= - 5 i + 4 - 5

Subtract the numbers:

4 - 5 = - 1

= - 5 i - 1

Rewrite in standard complex form:

- 1 - 5 i

= - 1 - 5 i

x \cdot (- 7)

x \cdot (- 4)

(2 x^{2} - 4 y^{5})^{2}

(- 6) (- 2)

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