What is sqrt(2^2+4^2+6^2) ?

The solution to sqrt(2^2+4^2+6^2) is 2sqrt(14)

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simplify sqrt(2^2+4^2+6^2)

simplify

2^{2} + 4^{2} + 6^{2}

214

Solution steps

2^{2} + 4^{2} + 6^{2}

2^{2} + 4^{2} + 6^{2} = 56

= 56

Prime factorization of

56 : 2^{3} \cdot 7

= 2^{3} \cdot 7

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

2^{3} \cdot 7 = 2^{2} \cdot 2 \cdot 7

= 2^{2} \cdot 2 \cdot 7

Apply radical rule:

ab = a b, a \geq 0, b \geq 0

2^{2} \cdot 2 \cdot 7 = 2^{2} 2 \cdot 7

= 2^{2} 2 \cdot 7

Apply radical rule:

a^{2} = a, a \geq 0

2^{2} = 2

= 2 2 \cdot 7

Multiply the numbers:

2 \cdot 7 = 14

= 214

(2 x + y^{2})^{2}

(6 x + 7) + (8 x^{2} + 5 x - 1)

- 27 \div 3

7 h - 5 - 4 h - 7

c^{- 3} c^{2}