What is (2x^{-3}y^{-4})(6x^{-4}y^7) ?

The solution to (2x^{-3}y^{-4})(6x^{-4}y^7) is (12y^3)/(x^7)

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simplify (2x^{-3}y^{-4})(6x^{-4}y^7)

simplify

(2 x^{- 3} y^{- 4}) (6 x^{- 4} y^{7})

\frac{12 y ^{3}}{x ^{7}}

Solution steps

(2 x^{- 3} y^{- 4}) (6 x^{- 4} y^{7})

Simplify

2 x^{- 3} y^{- 4} : \frac{2}{x ^{3} y ^{4}}

= \frac{2}{x ^{3} y ^{4}} \cdot 6 x^{- 4} y^{7}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

x^{- 4} = \frac{1}{x ^{4}}

= \frac{2}{x ^{3} y ^{4}} \cdot 6 \cdot \frac{1}{x ^{4}} y^{7}

Apply the fraction rule:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{2 \cdot 6 \cdot 1 \cdot y ^{7}}{x ^{3} y ^{4} x ^{4}}

Multiply the numbers:

2 \cdot 6 \cdot 1 = 12

= \frac{12 y ^{7}}{x ^{3} y ^{4} x ^{4}}

Simplify

\frac{y ^{7}}{y ^{4}} : y^{3}

= \frac{12 y ^{3}}{x ^{3} x ^{4}}

Simplify

x^{3} x^{4} : x^{7}

= \frac{12 y ^{3}}{x ^{7}}

\frac{1}{7} + \frac{1}{4}

\frac{11}{4} \cdot \frac{1}{7}

80 - 20

(y - 7) (y - 8)

125 x^{3}

What is (2x^{-3}y^{-4})(6x^{-4}y^7) ?
The solution to (2x^{-3}y^{-4})(6x^{-4}y^7) is (12y^3)/(x^7)