What is (k^2+9k-10)/(34)*2/(k^2-1) ?

The solution to (k^2+9k-10)/(34)*2/(k^2-1) is (k+10)/(17(k+1))

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simplify (k^2+9k-10)/(34)*2/(k^2-1)

simplify

\frac{k ^{2} + 9 k - 10}{34} \cdot \frac{2}{k ^{2} - 1}

\frac{k + 10}{17 ( k + 1 )}

Solution steps

\frac{k ^{2} + 9 k - 10}{34} \cdot \frac{2}{k ^{2} - 1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( k ^{2} + 9 k - 10 ) \cdot 2}{34 ( k ^{2} - 1 )}

Factor the number:

34 = 2 \cdot 17

= \frac{( k ^{2} + 9 k - 10 ) \cdot 2}{2 \cdot 17 ( k ^{2} - 1 )}

Cancel the common factor:

2

= \frac{k ^{2} + 9 k - 10}{17 ( k ^{2} - 1 )}

Factor

k^{2} + 9 k - 10 : (k - 1) (k + 10)

= \frac{( k - 1 ) ( k + 10 )}{17 ( k ^{2} - 1 )}

Factor

k^{2} - 1 : (k + 1) (k - 1)

= \frac{( k - 1 ) ( k + 10 )}{17 ( k + 1 ) ( k - 1 )}

Cancel the common factor:

k - 1

= \frac{k + 10}{17 ( k + 1 )}

3 x + 1 = x + 8

5 x^{2} - 6 x + 2 = 0

x^{\frac{3}{2}}

\frac{20 + 5 i}{20 - 5 i}

2 x - 1 = - 6

What is (k^2+9k-10)/(34)*2/(k^2-1) ?
The solution to (k^2+9k-10)/(34)*2/(k^2-1) is (k+10)/(17(k+1))