What is factor 16x^{12}-1 ?

The solution to factor 16x^{12}-1 is (4x^6+1)(2x^3+1)(2x^3-1)

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factor 16x^{12}-1

factor

16 x^{12} - 1

(4 x^{6} + 1) (2 x^{3} + 1) (2 x^{3} - 1)

Solution steps

16 x^{12} - 1

Apply exponent rules

= (4 x^{6})^{2} - 1^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(4 x^{6})^{2} - 1^{2} = (4 x^{6} + 1) (4 x^{6} - 1)

= (4 x^{6} + 1) (4 x^{6} - 1)

Factor

4 x^{6} - 1 : (2 x^{3} + 1) (2 x^{3} - 1)

= (4 x^{6} + 1) (2 x^{3} + 1) (2 x^{3} - 1)

\frac{4 ^{3}}{4 ^{- 3}}

(a^{3} b)^{4} (a b^{6})^{2}

2 x^{3} (9 x^{2} + 5 y)

(- 14) + (- 7)

6 x^{2} - 11 x y + 3 y^{2}

What is factor 16x^{12}-1 ?
The solution to factor 16x^{12}-1 is (4x^6+1)(2x^3+1)(2x^3-1)