What is (x^2-2x)/(x^2-4x+4) ?

The solution to (x^2-2x)/(x^2-4x+4) is x/(x-2)

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simplify (x^2-2x)/(x^2-4x+4)

simplify

\frac{x ^{2} - 2 x}{x ^{2} - 4 x + 4}

\frac{x}{x - 2}

Solution steps

\frac{x ^{2} - 2 x}{x ^{2} - 4 x + 4}

Factor

x^{2} - 2 x : x (x - 2)

= \frac{x ( x - 2 )}{x ^{2} - 4 x + 4}

Factor

x^{2} - 4 x + 4 : (x - 2)^{2}

= \frac{x ( x - 2 )}{( x - 2 ) ^{2}}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(x - 2)^{2} = (x - 2) (x - 2)

= \frac{x ( x - 2 )}{( x - 2 ) ( x - 2 )}

Cancel the common factor:

x - 2

= \frac{x}{x - 2}

(- 5 - 5 i) - (- 3 + 6 i)

\frac{4}{5 + 3}

(6)^{2} + (8)^{2}

8 x + 11 + 12 x - 1

\frac{6 + 8}{2}