What is (x^2+4x-5)/(x^2-2x+1) ?

The solution to (x^2+4x-5)/(x^2-2x+1) is (x+5)/(x-1)

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simplify (x^2+4x-5)/(x^2-2x+1)

simplify

\frac{x ^{2} + 4 x - 5}{x ^{2} - 2 x + 1}

\frac{x + 5}{x - 1}

Solution steps

\frac{x ^{2} + 4 x - 5}{x ^{2} - 2 x + 1}

Factor

x^{2} + 4 x - 5 : (x - 1) (x + 5)

= \frac{( x - 1 ) ( x + 5 )}{x ^{2} - 2 x + 1}

Factor

x^{2} - 2 x + 1 : (x - 1)^{2}

= \frac{( x - 1 ) ( x + 5 )}{( x - 1 ) ^{2}}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(x - 1)^{2} = (x - 1) (x - 1)

= \frac{( x - 1 ) ( x + 5 )}{( x - 1 ) ( x - 1 )}

Cancel the common factor:

x - 1

= \frac{x + 5}{x - 1}

3 x^{4} - 16 x^{2}

2 x^{2} - 2 x - 112

- 3 y - 5 x^{3} + 6 + 2 - 4 y + 5 y + 6 x^{3}

(\frac{5 x ^{- 2} y}{x ^{- 5}})^{3}

(5 n) (- 4 n^{2})

What is (x^2+4x-5)/(x^2-2x+1) ?
The solution to (x^2+4x-5)/(x^2-2x+1) is (x+5)/(x-1)