What are the solutions to the equation 5(y-4)^2=80 ?

The solutions to the equation 5(y-4)^2=80 are y=8,y=0

Find the zeros of 5(y-4)^2=80

The zeros of 5(y-4)^2=80 are y=8,y=0

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5 (y - 4)^{2} = 80

y = 8, y = 0

Solution steps

5 (y - 4)^{2} = 80

Divide both sides by

5

(y - 4)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

y - 4 = 16 : y = 8

Solve

y - 4 = - 16 : y = 0

The solutions to the quadratic equation are:

y = 8, y = 0

20 x - 17 > 4 x - 22

∣ 3 x - 7 ∣ = x + 1

30 - 9

x^{3} - 5 x^{2} + 2 x + 8 > 0

4 = \frac{1}{3} (4 x + 9)

What are the solutions to the equation 5(y-4)^2=80 ?
The solutions to the equation 5(y-4)^2=80 are y=8,y=0
Find the zeros of 5(y-4)^2=80
The zeros of 5(y-4)^2=80 are y=8,y=0