What is (2x-1)^2+8(2x-1)+12 ?

The solution to (2x-1)^2+8(2x-1)+12 is 4x^2+12x+5

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simplify (2x-1)^2+8(2x-1)+12

simplify

(2 x - 1)^{2} + 8 (2 x - 1) + 12

4 x^{2} + 12 x + 5

Solution steps

(2 x - 1)^{2} + 8 (2 x - 1) + 12

Expand

(2 x - 1)^{2} : 4 x^{2} - 4 x + 1

= 4 x^{2} - 4 x + 1 + 8 (2 x - 1) + 12

Expand

8 (2 x - 1) : 16 x - 8

= 4 x^{2} - 4 x + 1 + 16 x - 8 + 12

Group like terms

= 4 x^{2} - 4 x + 16 x + 1 - 8 + 12

Add similar elements:

- 4 x + 16 x = 12 x

= 4 x^{2} + 12 x + 1 - 8 + 12

Add the numbers:

1 - 8 + 12 = 5

= 4 x^{2} + 12 x + 5

u^{2} - 9

\frac{9}{6} \cdot \frac{4}{5}

2 (a + 1)^{2} - 3

\frac{x + 1}{x} - \frac{x}{x + 1}

(3 x - 6 y)^{2}