What is (x^2+2x-3)/(x^2+3x-4) ?

The solution to (x^2+2x-3)/(x^2+3x-4) is (x+3)/(x+4)

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simplify (x^2+2x-3)/(x^2+3x-4)

simplify

\frac{x ^{2} + 2 x - 3}{x ^{2} + 3 x - 4}

\frac{x + 3}{x + 4}

Solution steps

\frac{x ^{2} + 2 x - 3}{x ^{2} + 3 x - 4}

Factor

x^{2} + 2 x - 3 : (x - 1) (x + 3)

= \frac{( x - 1 ) ( x + 3 )}{x ^{2} + 3 x - 4}

Factor

x^{2} + 3 x - 4 : (x - 1) (x + 4)

= \frac{( x - 1 ) ( x + 3 )}{( x - 1 ) ( x + 4 )}

Cancel the common factor:

x - 1

= \frac{x + 3}{x + 4}

(2^{3})^{4} \cdot (2^{3})^{- 5}

- 1 x

(3 x^{- 2})^{- 4} x^{- 4}

9 + 2

\frac{5 ^{2}}{5}

What is (x^2+2x-3)/(x^2+3x-4) ?
The solution to (x^2+2x-3)/(x^2+3x-4) is (x+3)/(x+4)