What is 3(a+1)^2-(a+1)+4 ?

The solution to 3(a+1)^2-(a+1)+4 is 3a^2+5a+6

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simplify 3(a+1)^2-(a+1)+4

simplify

3 (a + 1)^{2} - (a + 1) + 4

3 a^{2} + 5 a + 6

Solution steps

3 (a + 1)^{2} - (a + 1) + 4

Apply the distributive law:

- (a + b) = - a - b

- (a + 1) = - a - 1

= 3 (a + 1)^{2} - a - 1 + 4

Expand

3 (a + 1)^{2} : 3 a^{2} + 6 a + 3

= 3 a^{2} + 6 a + 3 - a - 1 + 4

Group like terms

= 3 a^{2} + 6 a - a + 3 - 1 + 4

Add similar elements:

6 a - a = 5 a

= 3 a^{2} + 5 a + 3 - 1 + 4

Add the numbers:

3 - 1 + 4 = 6

= 3 a^{2} + 5 a + 6

- 4 - 5 i

\frac{( - 24 x + 16 )}{8}

25 + 16

\frac{4 a}{5} (10 a - 25 b)