What is 1/((\frac{1){x+9})+9} ?

The solution to 1/((\frac{1){x+9})+9} is (x+9)/(9x+82)

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simplify 1/((\frac{1){x+9})+9}

simplify

\frac{1}{( \frac{1}{x + 9} ) + 9}

\frac{x + 9}{9 x + 82}

Solution steps

\frac{1}{( \frac{1}{x + 9} ) + 9}

Apply rule:

(a) = a

(\frac{1}{x + 9}) = \frac{1}{x + 9}

= \frac{1}{\frac{1}{x + 9} + 9}

Join

\frac{1}{x + 9} + 9 : \frac{9 x + 82}{x + 9}

= \frac{1}{\frac{9 x + 82}{x + 9}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{x + 9}{9 x + 82}

\frac{108}{3}

- 2 x^{2} + 26 x - 44

3 x^{8} - 3

12 8^{\frac{2}{7}}

\frac{128}{18}

What is 1/((\frac{1){x+9})+9} ?
The solution to 1/((\frac{1){x+9})+9} is (x+9)/(9x+82)