What is ((n+2)!)/((n-1)!) ?

The solution to ((n+2)!)/((n-1)!) is (n+2)(n+1)n

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simplify ((n+2)!)/((n-1)!)

simplify

\frac{( n + 2 ) !}{( n - 1 ) !}

(n + 2) (n + 1) n

Solution steps

\frac{( n + 2 ) !}{( n - 1 ) !}

Cancel the factorials:

\frac{n !}{( n - m ) !} = n \cdot (n - 1) \dots (n - m + 1), n > m

\frac{( n + 2 ) !}{( n - 1 ) !} = (n + 2) (n + 1) n

= (n + 2) (n + 1) n

9 + \frac{1}{2}

9 - 220

16 x^{3} + 16 x^{2} - 9 x - 9

8 y^{2} + 7 x y - 2 y^{2} - 5 x y + 2 x

\frac{4}{30} + \frac{1}{20}