What is x^4(-2x)^3(6x^0)^{-2} ?

The solution to x^4(-2x)^3(6x^0)^{-2} is -(2x^7)/9

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simplify x^4(-2x)^3(6x^0)^{-2}

simplify

x^{4} (- 2 x)^{3} (6 x^{0})^{- 2}

- \frac{2 x ^{7}}{9}

Solution steps

x^{4} (- 2 x)^{3} (6 x^{0})^{- 2}

Simplify

(- 2 x)^{3} : - 8 x^{3}

= x^{4} (- 8 x^{3}) (6 x^{0})^{- 2}

Simplify

(6 x^{0})^{- 2} : \frac{1}{36}

= x^{4} (- 8 x^{3}) \frac{1}{36}

Apply rule:

a (- b) = - ab

x^{4} (- 8 x^{3}) = - x^{4} \cdot 8 x^{3}

= - x^{4} \cdot 8 x^{3} \frac{1}{36}

Simplify

x^{4} x^{3} : x^{7}

= - x^{7} \cdot 8 \cdot \frac{1}{36}

= - \frac{1}{36} \cdot 8 x^{7}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{1 \cdot 8 x ^{7}}{36}

Multiply the numbers:

1 \cdot 8 = 8

= - \frac{8 x ^{7}}{36}

Factor the number:

8 = 4 \cdot 2

= - \frac{4 \cdot 2 x ^{7}}{36}

Factor the number:

36 = 4 \cdot 9

= - \frac{4 \cdot 2 x ^{7}}{4 \cdot 9}

Cancel the common factor:

4

= - \frac{2 x ^{7}}{9}

\frac{3 x - 12}{- 2}

a^{2} - 16 a - 36

\frac{48}{- 6}

6 x^{2} - 7 x y - 5 y^{2}

\frac{48}{18}

What is x^4(-2x)^3(6x^0)^{-2} ?
The solution to x^4(-2x)^3(6x^0)^{-2} is -(2x^7)/9