What is (7-6i)-(4-8i) ?

The solution to (7-6i)-(4-8i) is 3+2i

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simplify (7-6i)-(4-8i)

simplify

(7 - 6 i) - (4 - 8 i)

3 + 2 i

Solution steps

(7 - 6 i) - (4 - 8 i)

Group the real part and the imaginary part of the complex number

(a + bi) - (c + d i) = (a - c) + (b - d) i

= (7 - 4) + (- 6 - (- 8)) i

Simplify

(7 - 4) + (- 6 - (- 8)) i : 3 + 2 i

= 3 + 2 i

10 x y^{4} (- 14 x y)

\frac{e ^{- 0.1} - 1}{- 0.1}

\frac{sin ( 3 x )}{cos ^{3} ( 3 x )}

12 x^{2} y^{3} - 16 x^{3} y^{2}

(a^{- 1} + b^{- 1})^{- 2}