What is (-2+3i)/(-2-3i) ?

The solution to (-2+3i)/(-2-3i) is -5/13-12/13 i

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simplify (-2+3i)/(-2-3i)

simplify

\frac{- 2 + 3 i}{- 2 - 3 i}

- \frac{5}{13} - \frac{12}{13} i

Solution steps

\frac{- 2 + 3 i}{- 2 - 3 i}

Multiply by the conjugate

\frac{- 2 + 3 i}{- 2 + 3 i}

= \frac{( - 2 + 3 i ) ( - 2 + 3 i )}{( - 2 - 3 i ) ( - 2 + 3 i )}

Simplify

\frac{( - 2 + 3 i ) ( - 2 + 3 i )}{( - 2 - 3 i ) ( - 2 + 3 i )} : \frac{- 12 i - 5}{13}

= \frac{- 12 i - 5}{13}

Rewrite in standard complex form:

- \frac{5}{13} - \frac{12}{13} i

= - \frac{5}{13} - \frac{12}{13} i

(3 a^{2} - a + 4)^{2}

(4 v^{3} w) (- 2 w^{3})^{2}

24.5

2^{- 4} \cdot 2^{- 3}

2 (- x)^{2}