What is i^2(3-i)(6-7i) ?

The solution to i^2(3-i)(6-7i) is -11+27i

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simplify i^2(3-i)(6-7i)

simplify

i^{2} (3 - i) (6 - 7 i)

- 11 + 27 i

Solution steps

i^{2} (3 - i) (6 - 7 i)

Apply imaginary number rule:

i^{2} = - 1

= - 1 \cdot (3 - i) (6 - 7 i)

Apply complex arithmetic rule:

(a + bi) (c + d i) = (a c - b d) + (a d + b c) i

= - 1 \cdot ((3 \cdot 6 - (- 1) (- 7)) + (3 (- 7) - 1 \cdot 6) i)

Simplify

(3 \cdot 6 - (- 1) (- 7)) + (3 (- 7) - 1 \cdot 6) i : 11 - 27 i

= - 1 \cdot (11 - 27 i)

Simplify

- 1 \cdot (11 - 27 i) : - 11 + 27 i

= - 11 + 27 i

(1 + 2 v) \cdot 5

\frac{w x y + w x z}{w y + w z + x y + x z}

(3 + j^{3}) (1 - j)

1 \frac{1}{4} \cdot 5

(\frac{4 b}{c ^{2} d})^{2}