What are the solutions to the equation 2x(x+2)=3(x-1) ?

The solutions to the equation 2x(x+2)=3(x-1) are x=-1/4+i(sqrt(23))/4 ,x=-1/4-i(sqrt(23))/4

Find the zeros of 2x(x+2)=3(x-1)

The zeros of 2x(x+2)=3(x-1) are x=-1/4+i(sqrt(23))/4 ,x=-1/4-i(sqrt(23))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x (x + 2) = 3 (x - 1)

x = - \frac{1}{4} + i \frac{23}{4}, x = - \frac{1}{4} - i \frac{23}{4}

Solution steps

2 x (x + 2) = 3 (x - 1)

Expand

2 x (x + 2) : 2 x^{2} + 4 x

Expand

3 (x - 1) : 3 x - 3

2 x^{2} + 4 x = 3 x - 3

Move

3

to the left side

2 x^{2} + 4 x + 3 = 3 x

Move

3 x

to the left side

2 x^{2} + x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 \cdot 3}{2 \cdot 2}

Simplify

1^{2} - 4 \cdot 2 \cdot 3 : 23 i

x_{1, 2} = \frac{- 1 \pm 23 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 1 + 23 i}{2 \cdot 2}, x_{2} = \frac{- 1 - 23 i}{2 \cdot 2}

x = \frac{- 1 + 23 i}{2 \cdot 2} : - \frac{1}{4} + i \frac{23}{4}

x = \frac{- 1 - 23 i}{2 \cdot 2} : - \frac{1}{4} - i \frac{23}{4}

The solutions to the quadratic equation are:

x = - \frac{1}{4} + i \frac{23}{4}, x = - \frac{1}{4} - i \frac{23}{4}

47 - 3 x = 32

2 x^{2} - 11 x + 12

\frac{3 ^{4} \cdot 27 \cdot 64}{2 ^{4} \cdot 2 \cdot 2 ^{3}}

What are the solutions to the equation 2x(x+2)=3(x-1) ?
The solutions to the equation 2x(x+2)=3(x-1) are x=-1/4+i(sqrt(23))/4 ,x=-1/4-i(sqrt(23))/4
Find the zeros of 2x(x+2)=3(x-1)
The zeros of 2x(x+2)=3(x-1) are x=-1/4+i(sqrt(23))/4 ,x=-1/4-i(sqrt(23))/4